I think the correct answer is that nobody knows - it all depends on the behaviour, or equation of state, of the dark energy.
If the dark energy takes the form of a cosmological constant, then the energy density due to dark energy will end up completely dominant as the universe expands.
The acceleration of the scale factor $a$ is given by
$$frac{ddot{a}}{a} = -frac{4pi G}{3}left(rho + frac{3P}{c^2}right) $$
where $rho$ is the energy density, and $P$ is the pressure. A cosmological constant has $P = -rho c^2$, which leads to
$$ ddot{a} = frac{8pi G rho a}{3}$$
So, if dark energy dominates, then $rho a$ increases with time, so the acceleration is positive and increasing with $a$ and hence time.
If matter dominates, which it did in the past, then $P simeq 0$ and $rho a propto a^{-2}$, so the acceleration is negative, with a magnitude that becomes smaller.
The transition from deceleration to acceleration happens when $rho_{Lambda} + rho_m + 3P/c^2= 0$. If we assume a cosmological constant with $P = -rho_{Lambda} c^2$, where $rho_{Lambda}$ is the dark energy density (which is constant), and $rho_m$ is the matter density, where $rho_m = rho_0 a_0^{3}/a(t)^3$ and $rho_0$ and $a_0$ are the present-day matter density and scale factor respectively. Thus
$$ rho_{Lambda} + rho_m -3rho_{Lambda} = 0$$
and the transition point occurs when $rho_m = 2 rho_{Lambda}$. But because $rho_{Lambda}/rho_0 = 0.7/0.3$, then
$$ rho_{Lambda} = frac{7rho_0}{3} = frac{7}{3}left(frac{a}{a_0}right)^3 rho_m$$
and so the scale factor at the time of transition from decleration to acceleration is found from
$$ rho_m = frac{14}{3}left(frac{a}{a_0}right)^3 rho_m,$$
$$ a = left(frac{3}{14}right)^{1/3} a_0$$
i.e. when the scale factor was 60% of the present day value. According to this cosmology calculator, this happened roughly 6 billion years ago.
Thus the universe was decelerating then accelerated. So clearly the acceleration now is increasing with time.
On the other hand, if for whatever reason, the dark energy started to "decay" then it might be that the acceleration would decrease.
