Tuesday, 31 March 2015

dg.differential geometry - If the second derivative of a function on $mathbb R^n$ is everywhere nondegenerate, does it follow that the first derivative is an injection?

The counter example given in the comments by Brian Conrad (and Dylan Thurston) is very nice. However, it oscillates wildly at $infty$, and I believe that if you assume some nice properties at $infty$ you will get a possitive answer.



Translating $f$ by a linear function does not change the assumptions on $f$ and so the claim is equivalent to the fact that all such $f$ has no or a unique critical points.



If we add assumptions such that e.g. the Conley index (or homotopy index) is well-defined and a sphere then this modified claim would follow. Indeed, if two or more critical points existed they would by assumptions be non-degenerate with same Morse index and a small pertubation would yield a Conley index which is a vedge of two or more spheres - a contradiction.

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