This can answered without any complicated maths.
It can be related to the following: Imagine you have N marked cards in a pack of m cards and shuffle them randomly. What is the probability that they are all at least distance d apart?
Consider dealing the cards out, one by one, from the top of the pack. Every time you deal a marked card from the top of the deck, you then deal d cards from the bottom (or just deal out the remainder if there's less than d of them). Once all the cards are dealt out, they are still completely random. The dealt out cards will have distance at least d between all the marked cards if (and only if) none of the marked cards were originally in the bottom (N-1)d.
The probability that the marked cards are all distance d apart is the same as the probability that none are in the bottom (N-1)d.
The points uniformly distributed on a line segment is just the same (considering the limit as m →∞). The probability that they are all at least a distance d apart is the same as the probability that none are in the left section of length (N-1)d. This has probability (1-(N-1)d/L)N.
Integrating over 0≤d≤L/(N-1) gives the expected minimum distance of L/(N2-1).
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