Sunday, 2 February 2014

nt.number theory - When does the zeta function take on integer values?

Regarding 3), this "Big Picard" stuff is serious overkill.



Think like an undergraduate real analysis student:



The p-series $zeta(p)$ converges for real $p > 1$, whereas $zeta(1)$ = sum of the harmonic series = oo.



An easy argument using (e.g.) the integral test shows that



$$lim_{p rightarrow infty} zeta(p) = 1$$



The function $zeta(p)$ is continuous in p [the convergence is uniform on right half-planes, hence on compact subsets], so by the intermediate value theorem it takes on every positive integer value $n ge 2$ at least once -- and, since it is a decreasing function of p, exactly once -- on the real line.



Thus $A_n$ is nonempty for all $n > 1$.



EDIT: Let me show that zeta(s) takes on all real values infinitely many times on the negative real axis.



For this, note that for all $n > 0$,



$$zeta(-(2n-1)) = - frac{B_{2n}}{(2n)}$$,



where $B_{2n}$ is the $(2n)$th Bernoulli number. It is known that the $B_{2n}$'s alternate in sign and grow rapidly in absolute value:



$$|B_{2n}| sim 4 sqrt{pi n} left(frac{n}{(pi e)^{2n}}right)$$



The claim follows from this and the Intermediate Value Theorem.

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